Question

At a cricket test match 2/7 of the spectators were in a covered place while 15000 were in open. Find the total number of spectators


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Answer 1

$\qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{\dfrac{dy}{d\theta}}{\dfrac{dx}{d\theta} \\\\ \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{ 2 \{cos 2 \theta - cos \theta \} }{-2 \{ sin 2 \theta + sin \theta \} }\\\\ \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{ cos 2 \theta - cos \theta }{-\{ sin 2 \theta + sin \theta \} }\\\\ \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{ 2 \{cos 2 \theta - cos \theta \} }{- \{ sin 2 \theta + sin \theta \} }$

Answer 2

Step-by-step explanation:

begin{gathered} \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{\dfrac{dy}{d\theta}}{\dfrac{dx}{d\theta} \\\\ \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{ 2 \{cos 2 \theta - cos \theta \} }{-2 \{ sin 2 \theta + sin \theta \} }\\\\ \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{ cos 2 \theta - cos \theta }{-\{ sin 2 \theta + sin \theta \} }\\\\ \qquad \dashrightarrow \sf \dfrac{dy} {dx} = \: \Bigg( \dfrac{ 2 \{cos 2 \theta - cos \theta \} }{- \{ sin 2 \theta + sin \theta \} }\\\\\end{gathered}