Math, asked by Aman1245, 1 year ago

AT A FAIR,A BOY TRIES HIS SKILL IN SHOOTING.HE WAS TO RECEIVE 20 RUPEES FOR HITTING THE BULL'S EYE. HE HAS TO PAY 8 RUPEES FOR MISSING THE BULL'S EYE. HE TRIED 50 SHOTS BUT RECEIVED ONLY 20 RUPEES. HOW MANY TIMES DID HE HIT THE BULL'S EYE?

PLZ GIVE SIMPLE AND EASY SOLUTION!!


Aman1245: please friends answer this question with solution. this is important for my exams

Answers

Answered by aman190k
31
Hey here is your answer
________________________

Let the no.of times he hits the ball be x
and the no.of times he miss the ball be y

then,
x + y = 50..............(1)

and a/c
20x + 8y = 20.................(2)

Now from equation (1)..
x = 50 - y

Putting the value of x in equation (2)
20 × ( 50 - y ) + 8y = 20
1000 - 20y + 8y = 20
1000 - 20 - 12y = 0
980 = 12y
y = 980/12

x = 50 - 980/12
x = (600 - 980)/12
x = - 380/12

dthh: thank you for your answers
Answered by sohamxav
54

Suppose , number of times he hits the bull's eye in 50 shots = x

Hits the bull's eye = ( x ) times

Misses the bull's eye = ( 50-x ) times

Money received = 20 * x

Money paid = 8 ( 50-x )

Total money he received ,

20*x-8(50-x) = 20

20x-400+8x = 20

20x+8x = 400+20

28x =420

x = 420/28

x = 15

Therefore, the boy hit the bull's eye 15 times.

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