Question

find three numbers in AP whose sum ........

Answer 1

This answer of your question

Answer 2

Answer:

let the number be ( a - d) , a ( a + d)

according to question,

a - d + d + a + d = 21

=> 3a = 21

=> a = 7

now,

their product = 231

=> ( a + d)(a -d)a = 231

=> ( a²- d²) ×7 = 231

=> 49 - d²= 33

=> 49 - 33 = d²

=> d² = 16

=> d = √16

=> d = ± 4

now,

taking d = + 4

then numbers are

3,7, 11

and taking d = -4

then numbers are,

11,7,3

$..$