find three numbers in AP whose sum ........
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786Cool786:
thank u vry much
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let the number be ( a - d) , a ( a + d)
according to question,
a - d + d + a + d = 21
=> 3a = 21
=> a = 7
now,
their product = 231
=> ( a + d)(a -d)a = 231
=> ( a²- d²) ×7 = 231
=> 49 - d²= 33
=> 49 - 33 = d²
=> d² = 16
=> d = √16
=> d = ± 4
now,
taking d = + 4
then numbers are
3,7, 11
and taking d = -4
then numbers are,
11,7,3
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