At a given place, a mercury barometer records
pressure of 0.70 m of Hg. What would be the
height of water column if mercury in barometer
is replaced by water ? Take density of mercury to be
13.6 x 103 kg m-3
Ans. 9.52 m
Answers
Answer:
At a place barometer records 70 cm of Hg. If Hg is replaced by water what would be the height
Given: The atmospheric pressure at one point is noted to be 70 cm of Hg.
70 cm= 0.70 m
The denisty of mercury is 13.6 times the density of water.
dm = 13.6 dw
Atmospheric pressure P = h x d x g
Let the height upto which the mercury is raised be hm and the density of mercury be dm.
Let the height upto which the water will be raised be hw and the density of water be dw.
hm x dm x g =hw x dw x g
hm x dm = hw x dw
rightwards double arrow h subscript w space end subscript equals h subscript m space d subscript m over d subscript g
rightwards double arrow h subscript w space end subscript space equals space 0.70 space cross times space 13.6
rightwards double arrow h subscript w space end subscript space equals space 9.52 space m e t r e s space
Thus, the water will raise to the height of 9.52 metres which makes it inconvenient to be used in barometer.
Answer:
Explanation:
Height of mercury in barometer : 0.70 m
If water is replaced by mercury then resulting reading : ?
Density of hg : 13600 kg/m^3
Density of water :1000kg /m^3
Height of water in barometer if replaced by mercury is
=>height of water =density of hg /density of water multiplied by height of mercury
=>h=13600/1000 x 0.70 => 13.6 x 0.70
= 9.52m
Therefore, the height of water when displaced by mercury is 9.52 m
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