At a given temperature the pressure of a Gass is reduced
to 75% of its initial value and the volume increases to by 40% of its initial value. Find the temperature if the initial
temperature was -10°c.
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Answer:
P1=P1
V1=V1
T1=263K
P1=75P1/100
V1=V+40/100
140V1/100
T2=?
According to the formula
P1V1/T1=P2V2/T2
P1V1/263=75P1/100×140V1/100×T2
1/263=10500/10000×T2
T2=10500/10000×263
T2=276.15
T2=3 (technically)
But normally T2=3.15℃
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