at a given temperature the ratio of RMS and average velocities is?
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Root-mean-square speed is the measure of the speed of particles in a gas which is most convenient for problem solving within the kinetic theory of gases. It is defined as the square root of the average velocity-squared of the molecules in a gas.
Sol. The two types of speeds are defined as; Root mean square speed (urms) = √(3RT/M) Average speed (uavg) = √(8RT/πM) For the same gas, at a given temperature, M and T are same, therefore u_rms/u_avg = √(3RT/M) ∶ √(8RT/πM) = √3 ∶ √(8/π )= √3 ∶ √2.54=1.085∶1
Sol. The two types of speeds are defined as; Root mean square speed (urms) = √(3RT/M) Average speed (uavg) = √(8RT/πM) For the same gas, at a given temperature, M and T are same, therefore u_rms/u_avg = √(3RT/M) ∶ √(8RT/πM) = √3 ∶ √(8/π )= √3 ∶ √2.54=1.085∶1
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R.M.S velocity=
![\sqrt{ \frac{3rt}{m} } \sqrt{ \frac{3rt}{m} }](https://tex.z-dn.net/?f=+%5Csqrt%7B+%5Cfrac%7B3rt%7D%7Bm%7D+%7D+)
Average velocity
![\sqrt{ \frac{8rt}{\pi \times m} } \sqrt{ \frac{8rt}{\pi \times m} }](https://tex.z-dn.net/?f=+%5Csqrt%7B+%5Cfrac%7B8rt%7D%7B%5Cpi+%5Ctimes+m%7D+%7D+)
Dividing both equations
we get
![\frac{rms}{average} = \sqrt{ \frac{24}{\pi} } \frac{rms}{average} = \sqrt{ \frac{24}{\pi} }](https://tex.z-dn.net/?f=+%5Cfrac%7Brms%7D%7Baverage%7D++%3D++%5Csqrt%7B+%5Cfrac%7B24%7D%7B%5Cpi%7D+%7D+)
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Average velocity
Dividing both equations
we get
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