Question

At a location where the acceleration due to gravity is 9.807 m/s2, the atmospheric pressure is 9.891 x 104 Pa. A barometer at the same location is filled with an unknown liquid. What is the density of the unknown liquid if its height in the barometer is 1.163 m?​

Answer 1

Answer:

sorry I didn't know bro

Answer 2

Given:

At a specific location acceleration due to gravity is, $\bold{g=9.807 ms^{-2}}$

Atmospheric pressure, $\bold{P = 9.891\times 10^4 Pa}$

Height of the unknown liquid in barometer is, $\bold{h = 1.163 m}$

To Find:

Density of the unknown liquid.

Solution:

Before starting we have to well aware of the formula, $\bold{P=\rho gh}$, this means the liquid of the barometer will rise until $\bold{\rho gh}$ equals the atmospheric pressure.

In the above equation $\rho$ is the density of the liquid.

∴$\bold{\rho = \frac{P}{gh} }$

Put the given values in the above equation and find the value of density ($\rho$)

$\rho = \frac{9.891\times 10^4}{9.807\times 1.163}$

$=> \rho = 8,672.1\hspace{1mm} kgm^{-3}$

∴ Density of the unknown liquid is $\bold{8,672.1\hspace{1mm} kgm^{-3}}$