At a particular point of the curve y = x 2 + k, the equation of the tangent is y = 6x - 7. find the value of the constant k .
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curve is a parabola x^2 =4/4(y-k) where a=1/4
tangent is (y+7)/6=x and t=1/6 so x= 2at y=at^2
x=1/12 and y=1/18
1/18=1/2+k
1/18 -9/18=k
k=-4/9
tangent is (y+7)/6=x and t=1/6 so x= 2at y=at^2
x=1/12 and y=1/18
1/18=1/2+k
1/18 -9/18=k
k=-4/9
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