At a point on level ground, the angle of a elevation of a vertical tower is found to be such that its tangent is 5/12, on walking 19.2m towards the tower, the tangent of the angle of elevation is 3/4. Find the height of tower
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Answer:
Let x be the height of the tower. As shown in the figure, let A be the initial position and B be the final position. Then,
h
192
+
x
=
5
12
12
h
=
960
+
5
x
⋯
⋯
(
1
)
h
x
=
3
4
4
h
=
3
x
x
=
4
h
3
Substituting the value of x in (1)
12
h
=
960
+
5
×
4
h
3
12
h
=
960
+
20
h
3
36
h
=
2880
+
20
h
16
h
=
2880
h
=
2880
16
=
180
meter
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