Question

at a sport camp there is sufficient food for 72 athletes to last 6 days . if 18 athletes are absent from camp how many more days can for other athletes? state the assumption made. answer=2days​

Answer 1

★ Given :

food can last 6 days for 72 athletes ..

★ To find :

Number of more days it can last if 18 athletes are absent.

★ Solution

Athletes left = total athletes - number of athletes absent.

72 - 18 = 54

We know that, it is in Inverse variation i.e The number of days increases with decrease in number of athletes ..

We know that in inverse variation..

→ $x_1 y_1 = x_2 y_2$

in our case,

$\begin{tabular}{ |c| c|} \cline{1 - 2} \sf Athletes(x)&Days(y) \\ \cline{1 - 2} x_{1} = 72& y_{1} = 6 \\ x_{2} = 54& y_{2} = ? \\ \cline{1 - 2} \end{tabular}$

by putting values

72 × 6 = 54 × y2

432 = 54 × y2

y2 = 432/54

y2 = 8

therefore , it will last for 8 days..

More days it can last =

8 - 6 = 2

→ therefore , it will last 2 more days if 18 athletes are absent.

Answer 2

Answer:

2 days

Step-by-step explanation:

Athletes            Days  

72          ⇒              6    

(72-18)54        ⇒    x

Equation which is formed is,

72*6 = 54x

432/54=x

x=8

So, for finding the extra days,

8-6=2