At a stop light, a truck traveling at 200 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 20m/s^2. How much time does the car take to catch up to the truck?
A. 5 sec B. 10 sec C. 15 sec D. 20
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B) 10secs
the velocity is changing @ 20m/s for d car( which is ntg but acceleration) , in order to catch up to d truck it has to reach 200m/s.
so time taken is
t = velocity / acceleration = 200/20 = 10secs
the velocity is changing @ 20m/s for d car( which is ntg but acceleration) , in order to catch up to d truck it has to reach 200m/s.
so time taken is
t = velocity / acceleration = 200/20 = 10secs
Anonymous:
20 is answer
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