Question

@
An Integer is divided by 8 giving
a remainder of 3. The resulting
quotient when divided by 7 gives
a remainder of 2. The resulting
quotient is then divided by 7 giving
a quotient of 1 and a remainder
of 6.
What will the finale
remainder be
if the order of the divisors is reversed ?
​

Answer 1

Answer:

Given-Divider=5,quotient=12,remainder=2

let x is the number can be written as

x=(divider×quotient)+remainder

x=(12×5)+2 =62

when the number is 60 divided by 7

62=(7×8)+6

Div-7,quo-8,remainder-6

the remainder of-6 Ans