Question

at at what temperature does the reduction of lead oxide to lead by carbon become spontaneous ?
PbO + C ------> Pb(s) + CO (g)
for the reaction above ∆H and ∆S at 25°c are 108.4 KJ /mol and 190 J/K Mol respectively.​

Answer 1

Answer:

∆H = 108.4kJ/mole

∆S = 190 J/kmol

∆G. = ∆H -- T∆S

at equilibrium.....∆G = 0

∆H =T ∆S

So..T = 108.4 x 1000 / 19

= 570.5 Kelvin

So... above 570.5 k...say 571 k

∆G = -ve and the reaction will become spontaneous..

Answer 2

Explanation:

equillibrium class 11.

Refer to the attachment

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