Question

At certain hill station pure water boils at 99.725°C if elevation constant of water is.513°C the B.P of.69m solution of urea will be

Answer 1

Delta tb = kb * m =0.513*0.69= 0.3539degree clecius Bpt. Of solution = 99.725degree celcius+0.3539degree celcius = 100.079degree celcius

Answer 2

Answer: $100.10^o C$.

Explanation:-

Elevation in boiling point is a  colligative property which is determined by the given formula:

$\Delta T_b=K_b\times m$

$\Delta T_b=T_b-T_b^0$ = elevation in boiling point

$K_b$ = boiling point constant =$0.513^0C$

m= molality = 0.69

$\Delta T_b=T_b-T_b^0=(T_b-99.725)^0C$

$(T_b-99.725)^0C=0.513\times 0.69$

$T_b=100.10^0C$

The boiling point of the solution is $100.10^o C$.