Question

At certain temperature ph of 10-2 m naoh is 10. Then the ph of neutral solution is

Answer 1

Let x be the max value of pH at that temperature (like 14 at 25° C)

pOH=-log[OH]

pOH=-log(10^-2)=2

pH+pOH=x (at that temperature)

pH=10 (given)

x=10+2=12

pH of neutral at that temperature is x/2=12/2=6