At constant temperature , a gas is at a pressure of 1080 nm of Hg . At what pressure it's volume will be decreased by 40 %
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Answered by
44
Heya....!!
Let the initial volume of gas ( V1 ) = V
so , 40% of initial volume = 40V/100 = 0.4 V
Final volume of gas ( V2 ) = V -0.4 = 0.6 V
initial pressure of gas ( P1 ) = 1080 mm of Hg .
Final pressure = ?
By Boyle's Law ,,
P1V1 = P2V2
P2 = 1080×V ÷0.6V
P2 = 1800 mm of Hg is the required answer .
HOPE IT HELPS U
Let the initial volume of gas ( V1 ) = V
so , 40% of initial volume = 40V/100 = 0.4 V
Final volume of gas ( V2 ) = V -0.4 = 0.6 V
initial pressure of gas ( P1 ) = 1080 mm of Hg .
Final pressure = ?
By Boyle's Law ,,
P1V1 = P2V2
P2 = 1080×V ÷0.6V
P2 = 1800 mm of Hg is the required answer .
HOPE IT HELPS U
Answered by
23
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