Question

At constant temperature and pressure 10 moles of ammonia gas occupies a 224000ml volume in a closed container with a movable piston.what will be the new volume of the gas when 2.5 moles of gas is removed from the container????​

Answer 1

Answer:

$\sf\fbox\red{Answer:-}$

Here only O 2

is gas due to which work is done by the system.

According to balanced equation,

2 moles of metallic oxide gives 1 moles of O2

∴ 4 moles of metallic oxide 2 moles O2

PV = nRT

V nRT P =

V

2 x 0.082 x 500

1

= 82.1L

Now,

W = -Pext AV

= -latm x 82.1L.

= -82.1Latm = 82.1 x 101.3 = -8316.7J =

-8.316kJ