Question

At constant temperature volume of a gas at 2 atm preassure is 10 L. What is the volume of the gas, if the preassure is increased by 4 atm

Answer 1

Given :

▪ Initial pressure of gas = 2atm

▪ Initial volume of gas = 10L

▪ Final pressure of gas = 4atm

(Temperature remains constant.)

To Find :

▪ Final volume of gas.

Concept :

❇ This question is completely based on the concept of Boyle's law.

❇ As per this law, At constant temperature, the pressure of a fixed ammount of gas varies inversely with its volume.

$\bigstar\bf\:P\propto\dfrac{1}{V}\\ \\ \bigstar\:\underline{\boxed{\bf{\red{P_iV_i=P_fV_f}}}}$

Calculation :

$\dashrightarrow\sf\:P_iV_i=P_fV_f\\ \\ \dashrightarrow\sf\:V_f=\dfrac{P_iV_i}{P_f}\\ \\ \dashrightarrow\sf\:V_f=\dfrac{10\times 2}{4}\\ \\ \dashrightarrow\sf\:V_f=\dfrac{20}{4}\\ \\ \dashrightarrow\underline{\boxed{\bf{\blue{V_f=5L}}}}\:\orange{\bigstar}$

Answer 2

Given,

$\bigstar$ Pressure of a gas = 2 atm

$\bigstar$ Volume of a gas = 10L

$\bigstar$ Final pressure of gas = 4atm

To find:-

Volume of the gas.

Now,......

P $\propto$ $\frac{1}{V}$

P(Initial) V(Initial) = P(final) V(final)

V(final) = $\frac{P(initial) V(Initial) } {P(final) }$

V(final) = $\frac {10×2} {4}$

V(final)= $\frac{20}{4}$

V(final) = 5L

so,

The volume of gas = 5L