Question

At constant temperature volumes of a gas at 2 atm pressure is 10 L what is the volume of the gas if the pressure is increased by 4 atm

Answer 1

Answer:

volume becomes 5L

Explanation:

as acc boyle's law PV=  constant (at const Temperature)

so P1/P2  =V2/V1

2/4=V2/10

V2 = 5 L

Answer 2

Given:

Initial pressure(p1) = 2 atm

Initial volume(v1) = 10 L

Final pressure(p2) = 4 atm.

Temperature is constant.

To find:

The final volume of the gas(v2)

Solution:

Since the temperature is constant throughout the process so, it can be done by applying Boyle's law formula.

From the Boyle's law equation we get that,

p1v1 = p2v2 [At constant temperature.]

⇒(2×10) = (4×v2)

⇒ 20 = 4v2

⇒ 4v2 = 20

⇒ v2 =(20÷4)

⇒v2 = 5 L.

So, the final volume of the gas will be 5 L.

Answer:

             The volume of the gas will be 5 L.