Question

At each corner of an equilateral triangle charges of +250 microcoloumb are placed in air. what will be the resultant electric potential at the centroid of the traingle whose distance frim each corner is 18 cm​

Answer 1

According to the question,

We have an equilateral triangle. At each of its corner there is a charge of +250 mC placed in the air. We are to find the electric potential at the centroid of the equilateral triangle.

We can derive it using the given formula;

net potential at a centroid = $V = 3\frac{kq}{r} = 3(\frac{9*10^9*250*10^-^6}{0.18}) = 3.75$ × $10^7 V$

Ans) The resultant electric potential at the centroid =​ 3.75 × $10^7 V$

Answer 2

Explanation:

r=18cm and it is s equilateral triangle so r is same from all three corners