Question

at present a father is 3 times as old as his son . after 12 years his age will be twice the age of his son. find their present ages.​

Answer 1

let son's age be x

father's age is 3x

after 12 years, son's age = x+12

father's age = 3x + 12

but it is given, father's age is twice of the son's. thus, 2(x+12)= 3x +12

2x + 24 = 3x +12

x = 12 =son's age

father's age = 3.12 = 36 yrs

Answer 2

Answer:

Step-by-step explanation:

Let the age of son be x years

Age of father at present = 3x years

After 12 years,

Son's age = (x+12) years

Father's age = (3x+12) years

ATQ,

2(x+12) = (3x+12)

=>2x+24 = 3x+12

=>3x-2x = 24-12

=>x = 12

Hence, present age of the son is

x = 12 years and father is 3x = 3×12 = 36 years.

Answer 3

Answer:

Step-by-step explanation:

Let the age of son be x years

Age of father at present = 3x years

After 12 years,

Son's age = (x+12) years

Father's age = (3x+12) years

ATQ,

2(x+12) = (3x+12)

=>2x+24 = 3x+12

=>3x-2x = 24-12

=>x = 12

Hence, present age of the son is

x = 12 years and father is 3x = 3×12 = 36 years.

Answer 4

Answer:

Step-by-step explanation:

Let the age of son be x years

Age of father at present = 3x years

After 12 years,

Son's age = (x+12) years

Father's age = (3x+12) years

ATQ,

2(x+12) = (3x+12)

=>2x+24 = 3x+12

=>3x-2x = 24-12

=>x = 12

Hence, present age of the son is

x = 12 years and father is 3x = 3×12 = 36 years.

Answer 5

Answer:

Step-by-step explanation:

Let the age of son be x years

Age of father at present = 3x years

After 12 years,

Son's age = (x+12) years

Father's age = (3x+12) years

ATQ,

2(x+12) = (3x+12)

=>2x+24 = 3x+12

=>3x-2x = 24-12

=>x = 12

Hence, present age of the son is

x = 12 years and father is 3x = 3×12 = 36 years.