at present,ankit is twice as old as his son.in four years,he will be four times as old as what his son was 9 years ago.find the present ages of both of them
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x = ankit's age (present)
y = ankit's son's age (present)
Present:
x = 2y
in 4 years
x + 4 = 4(y-9)
x+4 = 4y - 36
x = 4y - 40
subtracting both eq.
2y - 40 = 0
y = 40/2
y = 20
since, x = 2y
x = 2(20)
x = 40
y = ankit's son's age (present)
Present:
x = 2y
in 4 years
x + 4 = 4(y-9)
x+4 = 4y - 36
x = 4y - 40
subtracting both eq.
2y - 40 = 0
y = 40/2
y = 20
since, x = 2y
x = 2(20)
x = 40
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0
Answer:
Ankit age =40 years
Son age =20 years
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