Question

at present asha's age is a 2 more than the square of had a daughter Nisha age when nisha grows to her mother is present age Asha age Would Be One Less than 10 times the present age of Nisha find their present ages of both Asha and Nisha

Answer 1

let Asha age=A and Nisha age= N


A=2 + N2 .......(1)


present difference in age A-N years , so nisha will be of his mom's age after A-N years


After A-N years his mother's age = A+A-N = 2A-N


Now from question


2A-N = 10N -1


2A=11N-1


Put value of A from equation 1


4+2N2= 11N-1


2N2-11N+5=0


(2N-1)(N-5)=0


N=5, A=2+25=27

Answer 2

Answer:

Let, Nisha’s present age be = x year

Therefore, according to the first condition, Asha's present age = x2 + 2

Nisha grows to her mother's present age after [(x² + 2) – x] years.

Then, Asha's age will become (x² + 2) + [(x² + 2) –x] years.

• According to the question :

⟹ (x² + 2) + [(x² + 2) – x] = 10x – 1

⟹ 2x² – x + 4 = 10x – 1

⟹ 2x² – 11x + 5 = 0

⟹ 2x² – 10x – x + 5= 0

⟹ 2x (x – 5) –1(x – 5) = 0

⟹ (x – 5) (2x – 1) = 0

⟹ (x – 5) = 0 or (2x – 1) = 0

⟹ x = 5 or 1/2

Ignoring x = 1/2 because then Asha’s age = x² + 2 = which is not possible.

Hence, Present Age of Nisha = 5 years

And Present Age of Asha = x² + 2 = (5)² + 2 = 25 + 2 = 27 years