Question

At room temperature (27.0°C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω (Given that the temperature coefficient of the material of the resistor is 1.70 × 10⁻⁴ °C⁻¹)?​

Answer 1

Answer:

do 100×117

27.0° c×1.70×10-4° c-1

Answer 2

AnswEr:-

• The temperature of the element is 1027° C

Explanation:-

Room T = 27° C

Resistance of thr heating element at T, R = 100Ω

Let T2 is the increased temperature of the filament. Resistance of the heating element at T1 , R2= 117Ω .

Temperature co efficient of the material of the filament.

→ a= 1.70 × 10-⁴ C-¹

→ a = R1-R / R(T1- T)

→ T1- T = R1- R/ Ra

→ T1- 27 = 117-100/100(1.7×10-⁴)

→ T1- 27 = 1000

→ T1 = 1027° C

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