Question

At S.T.P. the density of CCl4 vapour in g/L will be nearest to:

Answer 1

Answer: Density of $CCl_4$ is 6.875 g/L.

Explanation: According to avogadro's law, 1 mole of every substance occupy 22.4 Liters at STP and weighs equal to its molecular mass.

Thus mass of $CCl_4$ at STP= 154 g

Volume occupied by $CCl_4$ at STP = 22.4 L

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}=\frac{154g}{22.4L}=6.875g/L$