At six months’ intervals A deposited of Rs. 1000 in a savings account which credit interest at 10% p.a.,
compounded semi-annually. The first deposit was made when A’s son was 6 months old and last deposit
was made when his son was 8 years old. The money remained in the account and was presented to the
son on his 10th birthday. How much did he receive? (1.06)16 = 2.1829)
plzz solve this sum with proper explanation I WILL MARK YOU AS BRAINLIST
Answers
Answer:
The amount is Rs.28746.72.
Step-by-step explanation:
Given : At six months’ intervals A deposited of Rs. 1000 in a savings account which credit interest at 10% p.a., compounded semi-annually. The first deposit was made when A’s son was 6 months old and last deposit was made when his son was 8 years old. The money remained in the account and was presented to the son on his 10th birthday.
To find : How much did he receive?
Solution :
Deposited on 6 Months and received on 10 Years.
Interest earned for 114 months =Months
Deposited on 12 Months and received on 10 Years
Interest earned for 108 months = Months
Deposited on 8 Years (96 months) Received on 10 Years
Interest earned for 24 months = Months
Amount Deposited every time = Rs 1000
Rate of interest = 10 % PA = 5% for 6 months
The amount became,
Therefore, The amount is Rs.28746.72.
28,756 Amount would be received at end of 10 Years
Step-by-step explanation:
Deposited on 6 Months Received on 10 Years
interest earned for 114 months = 19 * 6 Months
Deposited on 12 Months Received on 10 Years
interest earned for 108 months = 18 * 6 Months
Deposited on 8 Years (96 months) Received on 10 Years
interest earned for 24 months = 4 * 6 Months
Amount Deposited every time = Rs 1000
Rate of interest = 10 % PA = 5% for 6 months
Amount = 1000 * ( 1.05¹⁹ + 1.05¹⁸ + ............................................+ 1.05⁴)
= 1000 * 1.05⁴(1 + 1.05 +....................................................+ 1.05¹⁴ + 1.05¹⁵)
= 1000 * 1.05⁴ ( 1.05¹⁶ - 1)/(1.05 - 1)
= 1000 * 1.05⁴ (2.1829 - 1)/(0.05)
= 28,756
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