At some location on earth the horizontal component of earth’s magnetic field is 18 × 10⁻⁶ T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 A m is suspended from its mid-point using a thread, it makes 45° angle with horizontal in equilibrium. To keep this needle horizontal, the vertical force that should be applied at one of its ends is :
(A) 3.6 × 10⁻⁵ N
(B) 1.8 × 10⁻⁵ N
(C) 1.3 × 10⁻⁵ N
(D) 6.5 × 10⁻⁵ N
Answers
Answered by
4
Explanation:
The correct option is (2).!
Answered by
2
Answer:
The right option is option 'B'
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