At STP 2 gram of He gas (molar mass = 4 g) occupies a volume of ______
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11.2 L
Explanation:
1 mole of He gas i.e 4 grams occupies a volume of 22.4 L at STP
1 mole = 4 g
x mole = 2 g
∴ x = 2/4
= 0.5 moles of He gas
Volume occupy 0.5 mol of He = 0.5 × 22.4
= 11.2 L
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