Math, asked by gfnikalivoda, 4 days ago

k diminished by 20 plus 5 yields two.
The ratio of the numbers x and y is equal to one.
The product of e and f is equal to ten.
Two times the number s plus three is five
The total of four and p is less than two.
Three times the number f is greater than one.



Translate to Mathematical sentences

Answers

Answered by funwithstudies2304
0

Answer:

i. 20 - 7 = 5

ii. x : y = 1

iii. ef = 10

iv. 2s + 3 = 5

v. 4 + p < 2

vi. 3f > 1

Step-by-step explanation:

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Check for the first answer on the internet, because I am not sure about the first one

Answered by Dhruv4886
0

The required mathematical expressions are

1. k - 20 + 5 = 2             2. x/y = 1

3. ef = 10                        4. 2s + 3 = 5

5. 4 + p < 2                     6. 3f > 1  

Given:

1. k diminished by 20 plus 5 yields two.

2. The ratio of the numbers x and y is equal to one.

3. The product of e and f is equal to ten.

4. Two times the number s plus three is five

5. The total of four and p is less than two.

6. Three times the number f is greater than one.  

To find:

Translate the sentence into Mathematical sentences  

Solution:

1. k diminished by 20 plus 5 yields two  

This implies 20 is subtracted from k and added 5 which results in 2

=> k - 20 + 5 = 2

2. The ratio of the numbers x and y is equal to one.

=> x: y = 1 : 1

=> x/y = 1

3. The product of e and f is equal to ten.

=> e × f = 10

=> ef = 10

4. Two times the number s plus three is five

Here 2 times the s = 2s

=> 2s + 3 = 5

5. The total of four and p is less than two.

This implies adding 4 and p is less than 2

=> 4 + p < 2

6. Three times the number f is greater than one.  

=> Three times the number f = 3f

=> 3f > 1

Therefore,

The required mathematical expressions are

1. k - 20 + 5 = 2             2. x/y = 1

3. ef = 10                        4. 2s + 3 = 5

5. 4 + p < 2                     6. 3f > 1  

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