Question

At STP 56 CC of hydrogen sulphide is mixed with 60 CC of chlorine. Calculate the mass of Sulphur formed. ​

Answer 1

Answer:

Explanation:

H2S+CL2=S+HCl

First find volume at 1 am and 273k

For that there is a relation

Volume at stp /22700 =volume at 1 atm and 273k /22400

Volume /22400 = 0.00246

Moles of h2s =0.00246

Moles of cl2 = 0.00218

Limiting ratio = 0.00218

Moles of s formed = limiting ratio×coefficient

=0.00218

Mass of s formed = 0.07 gm

Answer 2

Answer:

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