Question

At STP, what is the volume of 7.08 mol of nitrogen gas?

Answer 1

At STP the Molar value of all gases is 22.4 dm³/mol.

7.08 mol of nitrogen at STP would occupy a volume of 7.08 ×22.4 = 158.592 dm³.

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Answer 2

The volume of 7.08 mol of nitrogen gas is 159 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number  of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 1 atm

V= Volume of the gas = ?

T= Temperature of the gas = 273 K      

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas = 7.08

$1\times V=7.08\times 0.0821\times 273$

$V=159L$

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