What is the mass of 5.42 cm3 of table sugar?
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I learnt that the density of table sugar is
700
k
g
⋅
m
−
3
. So the answer is a bit under
4
g
.
Explanation:
In handier units this is:
700
⋅
k
g
⋅
m
−
3
×
10
3
⋅
g
⋅
k
g
−
1
×
10
−
6
⋅
m
3
⋅
c
m
−
3
=
0.7
⋅
g
⋅
c
m
−
3
, or
0.7
⋅
g
⋅
m
L
.
So (finally) the answer to your question is
5.42
⋅
c
m
−
3
×
0.7
⋅
g
⋅
c
m
3
=
4
⋅
g
approximately!
It is a fact that sugar DOES NOT dissolve in hexanes. Given that
ρ
hexanes
=
0.67
⋅
g
⋅
m
L
, should sugar float in hexanes? Can you account for the fact that sucrose,
C
12
H
22
O
11
is insoluble in hexanes?
hope it help
mark as brainliest
700
k
g
⋅
m
−
3
. So the answer is a bit under
4
g
.
Explanation:
In handier units this is:
700
⋅
k
g
⋅
m
−
3
×
10
3
⋅
g
⋅
k
g
−
1
×
10
−
6
⋅
m
3
⋅
c
m
−
3
=
0.7
⋅
g
⋅
c
m
−
3
, or
0.7
⋅
g
⋅
m
L
.
So (finally) the answer to your question is
5.42
⋅
c
m
−
3
×
0.7
⋅
g
⋅
c
m
3
=
4
⋅
g
approximately!
It is a fact that sugar DOES NOT dissolve in hexanes. Given that
ρ
hexanes
=
0.67
⋅
g
⋅
m
L
, should sugar float in hexanes? Can you account for the fact that sucrose,
C
12
H
22
O
11
is insoluble in hexanes?
hope it help
mark as brainliest
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