Physics, asked by haribabuplates, 9 months ago

At t = 0, observer and source are at  same place. Now the source is projected with velocity 60route2 at 45. Natural frequency of source is 1000Hz. Find the frequency heard by the observer at t = 2s. Take speed of sound = 340m/s.​

Answers

Answered by khushikumariraj8083
0

Answer:

A higher frequency is received by the observer moving toward the source, and a lower frequency is received by an observer moving away from the source. In general, then, relative motion of source and observer toward one another increases the received frequency. Relative motion apart decreases frequency.

Explanation:

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