At t degree, Kw for water is 6.4x10–13. the pH of water at the degree will be
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TOPIC :- IONIC EQUILIBRIUM
CONCEPT :- Kw is called ionic product of water. Kw = [H+] [OH-]. And, pH = -log[H+]
SOLUTIONS
Given,
Kw = 6.4 × 10^-13
[H+]² = 6.4 × 10^-13
[H+] = 8 × 10-7
Thus,
pH = - log[8 × 10^-7]
=> pH = 7 - log8
=> pH = 7 - 2log2
=>pH = 7 - 0.6
=> pH = 6.4 Ans.
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