Question

At t minutes past 2 p.m. the time needed by the minutes hand of a clock to show 3

p.m. was found to be 3 minutes less than
t^2/4 minutes . Find t.

Answer 1

Given that At t minutes past 2 pm the time needed by the minute's hand of a clock to show 3 pm was found to be 3 minutes less than t^2/4 minutes.

$= \ \textgreater \ 2 + \frac{t}{60} + \frac{ \frac{t^2}{4} - 3 }{60} = 3$

$= \ \textgreater \ 120t + t + \frac{t^2}{4} - 3 = 180$

$= \ \textgreater \ \frac{t^2}{4} + t - 63 = 0$

$= \ \textgreater \ t^2 + 4t - 252 = 0$

= > t^2 - 14t + 18t - 252 = 0

= > t(t - 14) + 18(t - 14) = 0

= > (t + 18)(t - 14) = 0

= > t = -18, t = 14


The value of t cannot be negative, so t = 14.


Therefore the value of t = 14.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks