At t minutes past 2 pm the time needed by the minutes hand and a clock to show 3 pm was found to be 3 minutes less than t square upon 4 minutes . Find t
Answers
Answered by
9
HEYA MATE,
HERE IS UR ANSWER.
Thanks for asking this question.
Given time needed by the minutes hand show (t2/4) – 3
Hence the quadratic equation becomes, (t2/4) – 3 = 60 – t
(t2 – 12)/4 = 60 – t
(t2 – 12) = 240 – 4 t
t2 – 12 – 240 + 4 t = 0
t2 + 4t – 252 = 0
t2 + 18t – 14t – 252 = 0
t(t + 18) – 14(t + 18) = 0
(t + 18)(t – 14) = 0
(t + 18) = 0 or (t – 14) = 0
∴ t = - 18 or t = 14
Since t cannot be negative, t = 14
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
Given time needed by the minutes hand show (t2/4) – 3
Hence the quadratic equation becomes, (t2/4) – 3 = 60 – t
(t2 – 12)/4 = 60 – t
(t2 – 12) = 240 – 4 t
t2 – 12 – 240 + 4 t = 0
t2 + 4t – 252 = 0
t2 + 18t – 14t – 252 = 0
t(t + 18) – 14(t + 18) = 0
(t + 18)(t – 14) = 0
(t + 18) = 0 or (t – 14) = 0
∴ t = - 18 or t = 14
Since t cannot be negative, t = 14
I HOPE IT HELPS U.
Anonymous:
it wil be full now
yes i m in my home
No problem
come to my comment box
where i gave the answer
I can't
U do
yaar i said i gave one answer come there
hey i m sorry for what i said,bye i m going to uninstall the app,here is my whatsapp number 7007063644,if not then its kk,i will miss u always,bye
bye
Answered by
0
Hi this your answer . if like answer follow me
Attachments:
Similar questions