At 't' minutes past two p.m. the time needed by the minutes and of a clock to show 3pm.was found to be 3minutes less than t²/4 minute find t.?
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The minute hand is at t
Time needed by minute hand to show 3PM = 60 -t
According to the question ---
=> 60 - t = t^2/4 - 3
=> 60 - t =( t^2 - 12)/4
=> 4(60 - t) = t^2 - 12
=> 240 - 4t = t^2 - 12
=> - 4t = t^2 - 12 - 240
=> t^2 +4t - 252 = 0
=> D = b^2 - 4ac = 4^2 - 4*1*(-252)
= 16 +1008
= 1024
Now , -b +/- √D/2a
= -4 +/- 1024/ 2
there will be two roots
= -4 +1024/2 and -4 - 1024/2
= 14 and - 18
but time cannot be negative.
So t = 14
( attachment also)
I hope it helps you....
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