at the airport there is a moving walkway 500m long, which moves at a speed of 4km/h. Aditya and Ravi step on the walkway at the same time. Aditya walks at speed of 6km/h on the walkway,while Ravi stands still. when aditya comes to the end of the walkway . how far is he ahead of Ravi.
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Aditya will be be 450 m ahead of Ravi
Step-by-step explanation:
at the airport there is a moving walkway 500m long, which moves at a speed of 4km/h
500m = 0.5 km
Ravi stands still
=> Time taken by Ravi to cross Moving walk away = (0.5)/4 = 1/8 hrs
Aditya Walks at 6 km/hr & walkway at 4 km/hr
Effective speed = 10 km/hr
Time taken to cover 500 m = 0.5/10 = 1/20 hr
1/8 - 1/20 hr Aditya will walk at 6 km/hr speed
= (5 - 2)/40 hr
= 3/40 hr
Speed = 6 km/hr
Distance = (3/40) * 6 = 18/40 km
= 18 * 1000/40
= 450 m
Aditya will be be 450 m ahead of Ravi
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