At the foot of a mountain the elevation of
its summit is 45° After ascending 1000m
towards the mountain up a slope
of 30° inclination, the elevation is found
to be 60 Find the height of the mountain
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okheyyyyyy I am answering but pls mark as brainliest
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Let AB be the height of the mountain and above be the figure as described in the question.
In rt
Δ
E
F
C
,
→
sin
30
°
=
y
1
→
y
=
1
2
k
m
and
→
cos
30
°
=
a
1
→
a
=
√
3
2
k
m
In rt
Δ
ADE,
→
tan
60
°
=
x
z
→
√
3
=
x
z
→
z
=
x
√
3
In rt
Δ
ABC,
tan
45
°
=
A
B
B
C
=
x
+
y
a
+
z
→
1
=
x
+
y
a
+
z
→
a
+
z
=
x
+
y
→
√
3
2
+
x
√
3
=
x
+
1
2
→
x
−
x
√
3
=
√
3
−
1
2
→
x
(
1
−
1
√
3
)
=
√
3
−
1
2
→
x
⋅
(
√
3
−
1
)
√
3
=
(
√
3
−
1
)
2
→
x
=
√
3
2
k
m
Now, the height of the mountain
=
A
B
=
x
+
y
=
√
3
2In rt
Δ
E
F
C
,
→
sin
30
°
=
y
1
→
y
=
1
2
k
m
and
→
cos
30
°
=
a
1
→
a
=
√
3
2
k
m
In rt
Δ
ADE,
→
tan
60
°
=
x
z
→
√
3
=
x
z
→
z
=
x
√
3
pls understand it
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