At time t=0 a car has a velocity of 16m/s at the end of 4.0 s
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at time t=0 a car has a velocity of 16m/s. it slows down with an acceleration given -0.50t, in m/s2 for t in seconds. it stops at time t equal to-
one year ago
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As we have U=16m/s V=0 m/s ( at rest) a= -0.50t Using 1st equation of motion V=U+at 0=16+(-50t)dt -16= -50t×t/2 √16×2/50=t t=8s
one year ago
Answers : (2)
As we have U=16m/s V=0 m/s ( at rest) a= -0.50t Using 1st equation of motion V=U+at 0=16+(-50t)dt -16= -50t×t/2 √16×2/50=t t=8s
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