At time t = 0 particle starts moving along the x-axis . if Its kinetic energy increases uniformly with time t, the net force acting on it must be proportional to ? [AIEEE 2011]
(a) √t
(b) constant
(c) t
(d) 1/√t
Answers
Answered by
1
Answer:
since the kinetic energy increases uniformly hence rate of change of kinetic energy is constant
so does the power so you can write f.v=k
Answered by
31
Answer :
Given that, Kinetic energy of moving particle increases uniformly with time t
So we can say that,
- KE ∝ t
We know that, KE = 1/2 mv²
➙ 1/2 mv² ∝ t
➙ v² ∝ t
[∵ mass doesn't vary with time]
➙ v ∝ √t
Differentiating both sides wrt t, we get
➙ dv/dt = d(√t)/dt
➙ a ∝ 1/√t
➙ a = k/√t _____ (I)
Where k is a proportionality constant.
★ As per newton's 2nd law of motion,
➠ F = ma
From equation (I),
➠ F = mk/√t
➠ F ∝ 1/√t (mk = constant)
∴ (D) is the correct answer.
Cheers!
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