Question

check wether -4 and 4 are zero of polynomial p(x) = x²+16​

Answer 1

Answer:

None of them is a zero

Step-by-step explanation:

p(x)=x²+16

now case 1

p(4)=4²+16

=16+16

=32

∵32≠0

∴4 is not a zero

case 2

p(-4)=(-4)²+16

=16+16 {since square of a negative number is positive}

=32

∵32≠0

∴-4 is not a zero

Hence proved

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