At time t, the distanve s of a particle moving in a straight line is given by s=-4t^2+2t. Find the average velocity between t=2sec and t=8sec
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When t is equal to 2s then,Average velocity is equal to 10m/s.t is equal to 8 ,distance is 528 m . Average velocity is 66m/s
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Answer:
average velocity=42 m/sec
Explanation:
S=4t^2+2t
at t=2sec ,S=20m
at t=8, S=272
TOTAL DISTANCE= 272-20 =252m
TOTAL TIME= 8-2=6SEC
AVG VELOCITY= 252/ 6 = 42SEC
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