Question

At time t, the distanve s of a particle moving in a straight line is given by s=-4t^2+2t. Find the average velocity between t=2sec and t=8sec

Answer 1

When t is equal to 2s then,Average velocity is equal to 10m/s.t is equal to 8 ,distance is 528 m . Average velocity is 66m/s

Answer 2

Answer:

average velocity=42 m/sec

Explanation:

S=4t^2+2t

at t=2sec ,S=20m

at t=8, S=272

TOTAL DISTANCE= 272-20 =252m

TOTAL TIME= 8-2=6SEC

AVG VELOCITY= 252/ 6 = 42SEC