At two points on the opposite sides of a pole the angles of elevation of the top of the pole are 30' and 45. If the height of the pole is 20m, find the distance between the two points
k h ???
Answers
Answered by
2
Answer:
Let the height of pole be PQ=h m.
And QB=d be the distance between B and foot of pole.
tan60
0
=
d
h
3
=
d
h
⇒d=
3
h
....(1)
tan30
0
=
100−d
h
3
1
=
100−d
h
⇒100−d=
3
h
Substitute the value of d from the equation (1), we get
⇒−
3
h
+100=
3
h
⇒100=h(
3
+
3
1
)
⇒100=h(
3
3+1
)
By doing cross multiplication
⇒100
3
=4h
⇒h=25
3
m
Explanation:
princess96838
Answered by
4
Answer:
h = 25√3 m
Explanation:
Let the height of pole be PQ = h m. And QB = d be the distance between B and foot of pole.
tan 60⁰: - h d
d h √3* - ..(1)
tan 30⁰: = h 100 - d
Feedback
1 √3 → 100-d h 100 - d = 3h Substitute the value of d from the equation (1), we get h √3 + 100 = √3h =
(√3 + = 100 = h (v + ²) 1
By doing cross multiplication
100√3 = 4h
h = 25√3 m
Similar questions