At what altitude the value of g should become 1/4 on the surface of eartH
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Answer:
The height above the Earth's surface where the acceleration due to gravity at sea level reduce to 0.20% is 136090931 m=136090.931 km 136090931 m = 136090.931 k m..
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g'=g(1-2h/R)
g/4=g(1-2h/R)
1/4=1-2h/R
2h/R=3/4
8h=3R
h=3R/8
h=3/8×6 378.1 kilometers
h=2391.7875kilometers
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