Question

At what distance from a concave mirror of focal length 10 cm an object should be placed so as to obtain its 5 times enlarged (i) real and (i) virtual image. Also find the position of image in both the situations?​

Answer 1

Answer:

Explanation:

1/F=1/V-1/U

1/10=1/5x-1/x

1/10=x-4x/5x

x=-40

image will form on the left side of the mirror ,

also image will form behind center of curvature