Question

At what height above the earth surface, the value of g is half of its value on earth's surface ? Given its radius is 6400 km

Answer 1

Answer:

At what height above Earth's surface is the value of acceleration ... g = (GM)/r^2, where G is the Universal Gravitational Constant (6.67 x 10^-11 N m^2/kg^2), M is the mass of the Earth (6.0 x 10 ^ 24 kg) and r is the radius of the Earth (approximately 6.4 x 10^6 meters = 6400 km). This equation also works for any distance from the center of the Earth (beyond the surface).

Answer 2

As we know  g' = g/(1+h/R)2 g'= g/2 h=? R=6400km

Thus, g/g'=(1+h/R)2

2= (1+h/6400)2

h= 6400(√2-1)

= 2649.6 km