At what height above the earth surface will the acceleration due to gravity be half
Answers
Answered by
0
Acceleration due to gravity g due to EArth is given by the formula
g = G M / d² ---- (1)
G = Universal Gravitational constant.
M = Mass of Earth
d = distance of the point from the center of Earth
g on the surface of Earth = G M /R² --- (2)
We want height h such that g' = g/2 = G M /(R+h)² ---(3)
From (2) and (3) we get: GM/2R² = GM/(R+h)²
R+h = √2 R
h = (√2 - 1) R Answer
g = G M / d² ---- (1)
G = Universal Gravitational constant.
M = Mass of Earth
d = distance of the point from the center of Earth
g on the surface of Earth = G M /R² --- (2)
We want height h such that g' = g/2 = G M /(R+h)² ---(3)
From (2) and (3) we get: GM/2R² = GM/(R+h)²
R+h = √2 R
h = (√2 - 1) R Answer
kvnmurty:
:-)
Answered by
0
the answer is h = (√2-1)r
Similar questions