At what height does the earth's surface does the acceleration due to gravity decrease by 1%
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Hi friend here is your answer
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We know, g' = g(1 -2H/R)
So, (g'-g)/g =-2H/R
-1/100= -2H/R
H = R/200
= 6400/200
=32 Km ans.
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###################
We know, g' = g(1 -2H/R)
So, (g'-g)/g =-2H/R
-1/100= -2H/R
H = R/200
= 6400/200
=32 Km ans.
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