Question

At what height from the centre of the earth surface, the acceleration due to gravity will
be 1/4 th of its value on the surface of the earth.​

Answer 1

AT THE HEIGHT OF HALF EARTH THE OPERATION TAKE PLACE

Answer 2

Answer:

Hey mate here is your answer.//

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Explanation:

g = GM/r^2  ------ equation1,

"G" is a constant of proportionality,

"M" and m are the two masses exerting the forces,

"r" is the radius of earth.

"g'" is gravitational acceleration at height H from surface of the earth.

g'= GM/(r+H)^2 ------equation2,

Now the calculation goes as:

Divide the equation1 by equation2,

g/g' = (r+H) ^2/ r^2,

4/1 = (r+H) ^2/ r^2,

2/1 = r+H/ r ===>> r=H,

The height above the surface when the acceleration due to gravity will be 1/4th of its value on the surface of earth is equal to “r”(radius of the earth).

Hope it helps you.//✔✔✔

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